작성한지 5년 이상 지난 게시물입니다. 최신의 정보와 맞지 않는 내용을 포함할 수도 있습니다.

Someone asked me how to generate all possible permutations out of a given set and I thought it was kind of interesting to think about it. I was able to come up with a general solution pretty easily (thanks to all the algorithm and math classes I took!) and I would like to share it with everyone.

### Recursive solution

For a given set, S,

whereas + and - signs denote set addition and set subtraction respectively.

### Python implementation

def permutation(set):
if set == []:
return [[]]
else:
r = []
for i in xrange(0, len(set)):
for p in permutation(set[0:i] + set[i+1:]):
r.append([set[i]] + p)
return r

### Results

>>> print permutation([1, 2, 3])
[[1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 1, 2], [3, 2, 1]]

I wouldn’t say this particular implementation is the most efficient one, but at least we know it works with up to a certain size of set. Sadly, we all have machines with a finite size of memory, our machine will produce stack overflow if your set is too big.

I think languages like Haskell would work very efficiently with this kind of recursive solution due to its beautiful features like lazy evaluation, tail recursion, etc. Please feel free to share your solution or implementation.